What is the difference between $argv and $argc? Give example?

To pass the information into the script from outside, help can be taken from the PHP CLI (Command line interface) method. Suppose addition of two numbers has to be passed to PHP then it can be passed like this on the command line:
php add.php 2 3
Here the script name is add.php, and 2 and 3 are the numbers that has to be added by the script. These numbers are available inside the script in an array called $argv. This array contains all the information on the command line; the statement is stored as follows:
$argv[0]=add.php
$argv[1]=2
$argv[2]=3
So, $argv always contains at least one element — the script name.
Then, in your script, you can use the following statements:
$sum = $argv[1] + $argv[2];
echo $sum;
$argc is a variable that stores the numbers of elements in $argv. $argc is equal to at least 1, which is saved for the name of the script. Example is $argc=3 using the above statements.